this post was submitted on 02 Dec 2024
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Science Memes

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[–] RememberTheApollo_@lemmy.world 24 points 3 weeks ago (2 children)

Ive seen this claim a dozen times. It’s a disc shape. How this thing isn’t going to start flipping and curving its trajectory, or just plain old running out of energy due to air resistance, and not making it out of earth’s atmosphere is beyond me.

[–] finitebanjo@lemmy.world 13 points 3 weeks ago (1 children)

It didn't stay solid upon initial blast impact. Probably didn't even stay liquid.

[–] Crashumbc@lemmy.world 8 points 3 weeks ago (1 children)

Yeah it vanished because it vaporized.

[–] finitebanjo@lemmy.world 1 points 3 weeks ago (2 children)

I think they were able to track it for at least 2 frames, thus calculate it's speed.

[–] Klear@sh.itjust.works 10 points 3 weeks ago (2 children)

Nope, just one frame. Adds to the myth, when people don't know the exact speed.

[–] CheeseNoodle@lemmy.world 3 points 3 weeks ago (1 children)

tbf the calculated speed is actually roughly the minnimum based on its starting position and the frame it appeared in. it could have actually been going even faster.

[–] Klear@sh.itjust.works -1 points 2 weeks ago

Pretty sure that's not really true though.

[–] finitebanjo@lemmy.world 2 points 3 weeks ago (1 children)

One frame before the blast and one frame after, but semantics.

[–] victorz@lemmy.world 0 points 3 weeks ago (1 children)

I don't count having no visual indication of the object as "tracking" it, if we're talking semantics. One frame could equal an even faster speed than what it would minimally take to cross the entire width of the image at some trajectory vector. For other vectors, it could be (much) less (like not passing straight through the image from on side to the opposite side, e.g.).

It's important to not hang too hard on this as the escape speed is dependent on air resistance, or rather lack thereof. Those escape speed numbers are defined along with the assumption of zero air resistance or other forces acting on the object.

[–] finitebanjo@lemmy.world 2 points 2 weeks ago (1 children)

You can use the frame from before to calculate the MINIMUM speed. It could have been going even faster.

[–] victorz@lemmy.world -1 points 2 weeks ago (1 children)

Or slower, depending on trajectory across the image.

[–] finitebanjo@lemmy.world 1 points 2 weeks ago (1 children)

No, not really. The object was placed directly above the payload beneath a 150M straight borehole. If there was some sort of angle to the hole them I'm sure the researchers would have accounted for it.

[–] victorz@lemmy.world -1 points 2 weeks ago (1 children)

Right. Then the angle is such that you could calculate it. But it still depends on the trajectory, so that's not wrong, for whoever down voted...

[–] finitebanjo@lemmy.world 1 points 2 weeks ago (1 children)
[–] victorz@lemmy.world -1 points 2 weeks ago (1 children)

About what am I confused? How about you present an argument instead of just down voting? Please elaborate, thank you.

[–] finitebanjo@lemmy.world 1 points 2 weeks ago* (last edited 2 weeks ago) (1 children)

Idk what you think trajectory means but they know the angle the steel cap shot off at and they know the angle and distance from which the high speed camera viewed it. There is no room for ambiguity, they calculated the minimum speed. There are no outside forces that could have curved the shot, either. An 900kg object going any number of kilometers per second won't be effected by windspeed for example.

You're just making an ass of yourself, speaking nonsense.

[–] victorz@lemmy.world -1 points 2 weeks ago (1 children)

Trajectory means what it means. Look it up and we'll have the same understanding of it.

You're saying the trajectory is known, and I'm saying that in that case what you've been saying should be correct. Maybe if you fuckin relax and don't attack someone just because you don't understand what they're saying you'd not come off as such an asshole. Jesus Christ, Mr. Hothead.

An 900kg object going any number of kilometers per second won't be effected by windspeed for example.

Uh. Excuse me? How much do you think an aeroplane might weigh? 😆 Probably more than 900 kg. And the wind speed is probably not the issue. It would be the drag. 👌

So anyway. Let's relax in the next comment, shall we? Let's have a nice discussion from now on, no attacking. That would be cool, and adult.

[–] finitebanjo@lemmy.world -1 points 2 weeks ago (1 children)
[–] victorz@lemmy.world -1 points 2 weeks ago

Very eloquent rebuttal. 👌 Big L. 😆

[–] merc@sh.itjust.works -1 points 2 weeks ago (1 children)
[–] victorz@lemmy.world 1 points 2 weeks ago
[–] gens@programming.dev 5 points 3 weeks ago (2 children)

Take a coin and trow it as hard as you can. The curving is not that much.

[–] RememberTheApollo_@lemmy.world 3 points 3 weeks ago

If it’s like a frisbee, yeah, but it still curves. Now start it spinning like spinning a coin on edge. The curving will be much more dramatic.

[–] merc@sh.itjust.works 1 points 2 weeks ago (1 children)

Throw it into water or gelatin. At thousands of metres per second the air is going to seem much more dense.

[–] gens@programming.dev 2 points 2 weeks ago (1 children)

I don't have the arm strength to trow anything at the speed needed to make your analogy work.

[–] merc@sh.itjust.works 1 points 2 weeks ago

Hit the gym, delete the lawyer, face the book.