this post was submitted on 22 Jan 2024
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Pi is infinite so every combination/string of numbers is in there, if we calculated enough you could find a billion 2s next to each other
You can look through the first trillion here
https://archive.org/details/pi_dec_1t
Though it’s a bunch of downloading
Not necessarily. It could just become a series of 1's repeating forever. Nothing would require it to contain all strings of numbers.
If that happens in a number, then it is rational. Pi is not rational, so that will never happen in pi.
The point of pi is that it’s non-repeating
Take a look at 0.101001000100001... This number is also non-repeating, but obviously doesn't contain all numbers with finite digits.
The property you're looking for is called to be a normal number. Pi is assumed to be one, but it hasn't yet been proven.
However, in a sense this is an unremarkable property as almost all real numbers are normal. :)
I was just claiming possibility because we haven’t calculated the infinite string
At work at the moment so can't go deep into it. But I think you misunderstand what non repeating numbers mean. Of course there are repeating numbers within pi which is fine, the issue would be if ALL the digits were to simply cycle over and repeat themselves. If however there are a few trillion digits then a series of 1's and 0's for ever, pi is still non repeating
Did you read what I responded to?
I did read it, I also wrote it. Wasn't trying to put you down or anything just sharing a bit of knowledge I found interesting. I know many people (my self included at one point) assumed pi would have to include everything when that just isn't true. Apologies if I did a bad job explaining it though
I wasn’t clear then, it’s not that it has to
It’s that it can until calculated