MikeHfuhruhurr

joined 1 year ago
[โ€“] MikeHfuhruhurr@beehaw.org 4 points 1 year ago (2 children)

Probably an emerald spoon in his case.

[โ€“] MikeHfuhruhurr@beehaw.org 9 points 1 year ago (1 children)

but if you sell your account you can get hundred of dollars! That's upwards of $9 a year of pure profit.

undefined> This will only further the โ€œ5 Mods Control 92 Of The Top 500 Subsโ€ issue and lead to overall less happy, less engaged users.

With that many subs, they couldn't be good mods even if they wanted to. It is truly only a power trip and badge collecting at that point.

It's like bragging that they're the CEO of 3 companies...ok so you're doing a terrible job managing 3 companies instead of trying to do good at 1.

Great point! It's been a while since my degree (and I don't use it), so I knew I'd probably get something wrong.

[โ€“] MikeHfuhruhurr@beehaw.org 18 points 1 year ago* (last edited 1 year ago) (3 children)

Yes! There's actually two facets to consider:

  1. Infinities can be countable or uncountable:

    • The set of integers is a countable infinity. This is pretty obvious, since you can easily count from one member to the next.

    • The set of irrational numbers is an uncountable infinity. This is because if I give you one member, you can't give me an objectively "next" one. There's infinitely many choices.

      Example: I say what's the next member of the set of irrational numbers after 1.05? Well, there's 1.050001, 1.056, etc.

  2. Can a member of an infinite set be mapped to a corresponding member of another infinite set? And if so, how?

    Spoiler, there are three different ways: surjective, injective, and bijective.

In this situation, the sets are both countable. QA can open bug #1, bug #2, etc. It's also - for now - at least a surjective mapping of Starfield bugs -> Skyrim bugs. Because they're both countable, for each bug in Starfield you can find at least one bug in Skyrim (because it's a known bigger set at the moment).

But we don't know more than that right now.