this post was submitted on 01 Nov 2023
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https://realpython.com/python-modulo-operator/#how-to-check-if-a-number-is-even-or-odd
I just wonder why module is the wrong solution.
Not neccessarily wrong, but you could also check the first bit. If it's 1 the number is uneven, if it's 0 the number is even. That seems to be more efficient.
That’s what I was thinking too… Although, I wouldn’t be surprised if most languages convert modulo 2 to this automatically.
That could also be the case.
That’s the main issue with premature optimization: do it the “optimized” way and it may still be inefficient, or do it the obvious way and let the compiler turn it into its most optimized form. (Of course, not the case with all languages, but most mainstream compilers optimize the code to a decent extent.)
Modern compilers and interpreters are smart enough to figure out what you're trying to do and automatically do that for you.
Huh... That makes sense. Til. Ran some tests but speed is pretty similar. Only 4% faster using bitmath or 300 milliseconds difference after 10mil runs.