this post was submitted on 11 Oct 2023
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Well there is normalization , regularization, and standardization, but it basically depends on what you want to do and what implications that has for your data.
X is the set and x is a value in that set.
So:
1 - { [ max(X) - x ] / [ max(X)- min(X) ] }
or alternatively,
[x- min(X)] / [max(X)-min(X)]
Should do what you are asking, which sounds like normalization. That will normalize your values between 0 and 1. However, it wont do anything about your data being skewed to one side or the other. So the mean of this value won't be 0.5, the halfway point between 0 and 1.
If you want something like that, you will need to standardize your data prior to running the above algorithm:
Something like:
[ x - mean(X) ] / std(X)
This will center your data around 0. If you then apply the first function (normalization), it should now be centered around 0.5 (even if it is not normally distributed).
OP might also be interested in the reverse operation. If s is your number from 0 to 1, the corresponding position in the "real" space is min + s * (max-min), which can also be written as (1-s)min + smax . This is sometimes called a linear interpolation, or a weighted average. Note that you can also use the same formulas with s smaller than zero and larger than one, thus performing linear extrapolation. Finally, these same formulas apply in higher dimensions, just think of min and max as the coordinates of two vectors, and appy these formulas for each coordinate, and you get linear interpolation between your two vectors.