this post was submitted on 06 Oct 2023
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Leibnitz Integral [rule] (feddit.de)
submitted 1 year ago by theFibonacciEffect@feddit.de to c/196@lemmy.blahaj.zone
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[–] lgstarn@kbin.social 2 points 1 year ago

For number 4 (or maybe a new number), if a(x) and b(x) are constant, the derivatives d/dx a(x) and d/dx b(x) are zero, so all that is left is that d/dx becomes a partial derivative and can move inside the integral.